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In Reply to: Re: That's not what my CCA guy said, but what does posted by Jim in Oregon on July 16, 2000 at 23:52:03:
According to the info given, "The number of tickets sold determines the number of cars given away. Last year we had 13 winners. If in the last group of ticket requests there are less than 2500, the winner of this drawing may be awarded a cash prize".
Given the same number of tickets as last year sold as an example (13 lots of 2500=13 winners), each one of your 5 tickets would go into 1 of 2500 lots. Thus you would be entered into 5 of the 13 lots. They then draw 13 tickets, one from each lot...you have 5 tries to win in the 5 of 13 lots you're entered for an overall chance of 5 of 2500 or 1/500. I always buy 5 tickets.
Lets say you buy 5 tickets.. the options are
handled. Options are:
1) as you suggest, enter each ticket into a different 1 in 2500 pool (so you have 5, 1 in 2500 chances of winning) or
2) more likely, all 5 tickets will be entered in the same pool (so you have a 5 in 2500 chance of winning)
MBC
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